How would you read and solve this?

Roses-are-Rosie Resident math genius, get over here!

Quote from bethesda

Oh and put Bang Chan on the right side of your signature instead of Yang Jeongin since you appreciate Bang Chan more than Yang Jeongin I think.

Generally, yes, but I still like I.N. a ton too. Plus, he was the one in the picture and in the gif, so I thought it made more sense to mention him in that context.

I think I learned how to solve this exact type of problem in either grade 11 or grade 12, if you didn't learn it in school yet then you should just wait until they teach you how to do it

Idk how you don't know how to read this, surely you know what a fraction is (according to Google you learn about fractions in grade 3)

If x is greater than 3, which of the following is equivalent to 1/ [ 1 / (x+2) + 1 / (x+3)]?

1 divided by [ (1 divided by x+2) plus (1 divided by x+3)]

A) (2x + 5) divided by (x^2 + 5x + 6)

B) (x^2 + 5x + 6) divided by (2x + 5)

This is a solution video for the problem

Seeing all that makes me think I did right by not taking maths

Ez pz you just replace x by 4.

To be more rigorous you multiply the numerator and denominator by (x+2).(x+3) but it takes more time.

Let T=1/[1/(x+2)+1/(x+3)]

just simplify step by step

now let G = 1/(x+2)+1/(x+3)

meaning T= 1/G

now simplify G

G=1/(x+2)+1/(x+3)

use cross multiply to get common denominator

hence common denominator is (x+2)*(x+3)

G=[(x+3)+(x+2)]/[(x+2)*(x+3)]

now simplify numerator

G=(2x+5)/[(x+2)*(x+3)]

now simplify denominator

G= (2x+5)/(x^2+5x+6)

Since T=1/G

T=1/[(2x+5)/(x^2+5x+6)]

simply again

T= (x^2+5x+6)/(2x+5)

Hence T=1/[1/(x+2)+1/(x+3)]= (x^2+5x+6)/(2x+5)

meaning the answer is B on the paper

Quote from Ves

Is this your homework?

Another nerd