math game #1

i would try this if i could be bothered but i can't so..

10 akorns wee woo

okk so x is 341

bASICALLY

bruh im lazy so let's just call (x + 19)/20 "a" lmao

so 20a + 1 | 19

so 19a + a + 1 | 19

a + 1 | 19

a ≡ 18 mod 19 wee woo

a's smallest value is 18 obv and since (x+19)/20 = 18, x = 341 yayay

Girl I didn't come here to do math

This shit is easy lmao..

So if we assume x is 341, if we add by 19, we get 360. Divide 360 by 20 and you get a whole number with no remainder. I know this because I tried other numbers to replace x and nothing would divide evenly except if I replaced x with 341.

For the other part of the problem, if we replace the x with 341 and add by 20, we get 361 and that can be evenly divided by 19.

The smallest natural x is 341 and the problem won't work if you use another number.