Difficulty level: Fifth grade
x+19 can be divided by 20, x+20 can be divided by 19, so find the smallest natural x
prize 10 akorns, should show the method not just answer
Difficulty level: Fifth grade
x+19 can be divided by 20, x+20 can be divided by 19, so find the smallest natural x
prize 10 akorns, should show the method not just answer
i would try this if i could be bothered but i can't so..
10 akorns wee woo
okk so x is 341
bASICALLY
bruh im lazy so let's just call (x + 19)/20 "a" lmao
so 20a + 1 | 19
so 19a + a + 1 | 19
a + 1 | 19
a ≡ 18 mod 19 wee woo
a's smallest value is 18 obv and since (x+19)/20 = 18, x = 341 yayay
Girl I didn't come here to do math
This shit is easy lmao..
So if we assume x is 341, if we add by 19, we get 360. Divide 360 by 20 and you get a whole number with no remainder. I know this because I tried other numbers to replace x and nothing would divide evenly except if I replaced x with 341.
For the other part of the problem, if we replace the x with 341 and add by 20, we get 361 and that can be evenly divided by 19.
The smallest natural x is 341 and the problem won't work if you use another number.
Don’t have an account yet? Register yourself now and be a part of our community!